NBA fans love to resolve a hypothetical scenario, whether it is a debate about which player is better than the other or which team would come up victorious in an imaginary matchup. These discussions are normal around the NBA world, and they won’t stop happening soon.
One of the questions that spark the most heated debates pushes fans to pick between a group of stars and remove one from the starting lineup. Sometimes this is really easy, but recently, Timeless Sports shared an interesting post with six NBA legends, asking fans which player comes off the bench if they played on the same team.
Michael Jordan, LeBron James, Kobe Bryant, Kevin Durant, Shaquille O’Neal, and Tim Duncan are featured on this incredible team, which made fans select which star would be out of the starting lineup if they were all together on the same squad.
While some picked Kobe Bryant and Tim Duncan, others mentioned LeBron James, but Kevin Durant was the one who got the most votes, as fans couldn’t see him playing over the other five stars.
Tim
Kobe
Kobe
KD
Kd
KD
KD
Lebron at the 1 Jordan 2 Kd 3 Tim 4 shaq 5. Sorry Kobe ♂️
All y’all saying Duncan don’t know basketball
KD Easily
Lebron comes off the team
kd or lebron
Durant might not even play
KD no question
Kd.. easy for me
We all know KD would probably be injured or demanding a trade..
Duncan easy
MJ and Kobe damn sho ain’t coming off the bench
Durant easy
Lebron pg kobe sg jordan sf duncan pf shaq c kd 6th man
MJ and Kobe damn sho ain’t coming off the bench
Lebron pg kobe sg jordan sf duncan pf shaq c kd 6th man
Yall might not like Bron but let’s be serious here
This was an interesting exercise, and one would think it would have been harder for fans, but some of them didn’t even think twice before picking Durant. The Brooklyn Nets superstar is anything but a fan favorite right now, which could be hurting his chances to make it over the rest of the legends in the eyes of many fans. This team would be unbeatable, and whoever went to the bench would be a lock for the 6th Man of the Year award.
