Cam Reddish has been mentioned in trade rumors for a while now, and that doesn’t seem to be stopping anytime soon. The New York Knicks player hasn’t had the best tenure in New York, failing to make an impact on the team, which never really opened its arms to him.
Now, Reddish might be out of the Knickerbockers, and a host of teams are reportedly interested in his services. This has been a recurrent topic around the league this season and it seems like the forward could be done with New York after his tumultuous tenure.
A couple of teams could use his services, from contenders to teams trying to have a better record in their respective conferences. Reddish could soon join a different team and there are two that looked like the best candidates for him to continue his career.
Cam Reddish Drawing A Lot Of Interest Around The League
According to Mike Scotto of HoopsHype, the Knicks have revealed their asking price for the player, and some teams have already made their interest in him clear. Among them, the Los Angeles Lakers and Milwaukee Bucks appear to have the biggest chances to land him.
“The Knicks are willing to part with Reddish for two second-round picks, league sources told HoopsHype. The Lakers, Bucks, and other teams have inquired about the asking price for Reddish, who was shooting a career-high 44.9 percent from the field before being benched, HoopsHype has learned.”
Reddish isn’t posting big numbers this season, which perfectly explains how little time he’s had on the Knicks. At the time of writing, he’s averaging 8.4 points, 1.6 rebounds, and one assist per game, which doesn’t look good for a lot of people. Still, Cam could join a team and prove that he’s very valuable in the league.
It’s unclear when and where he will be traded, but he’s having plenty of suitors for his services right now. The Lakers
We sincerely appreciate and respect you as a reader of our site. It would help us a lot if you follow us on Google News because of the latest update.
Thanks for following us. We really appreciate your support.